Acar tire is filled with air at pressure 325000 pa at 283 k. if the tire warms up to 302 k, what is the new pressure of the tire (unit = pa)

346819 Pa       or   ,347000 Pa in 3 significant figures

Explanation:

P1= 325000Pa , T1= 283K ,

P2=?  T1= 302 K

as here volume and mass both are constant so using ratio method for pressure temperature law we have P1/T1 = P2/T2

THIS WE CAN ALSO OBTAIN BY RATIO METHOD FOR GENERAL GAS LAW AS

P1V1/(m1T1 ) =  P2 V2/ (m2 T2)

IF V1 = V2 =V AND m1=m2=m then expression reduces to

P1/T1 = P2/T2

or P2 = (P1/T1)×T2

P2 = (325000/283) × 302

P2 = 1148.41×302

P2=346819

P2 = 347000 Pa in 3 significant figures

347000

Explanation:

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their crystal patterns have been disrupted by stress

d. air pressure decreases as altitude increases.