Suppose nasa wants a satellite to revolve around earth 5 times a day. what should be the radius of its orbit if we neglect the presence of the moon? (g=6.67*10^ -11 n*m^2/kg^2, mearth=5.97*10^24 kg). answer is 1.44*10^7 m

r = 1.44 × m

Explanation:

given data

satellite to revolve = 5 time a day

G = 6.67 × Nm²/kg²

Mass earth = 5.97 ×  kg

to find out

radius of its orbit

solution

first we get here Time taken for one complete revolution that is

time taken =

time taken = 4.8 hours

time taken = 4.8 hours × 3600 sec

time taken = 17280 sec

and

time is express as

T = 2π ×    .............1

put hre value we get

17280 = 2π ×

solve it we get

r = 1.44 × m

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