Acannon launches a projectile at an angle of 22 degrees off the horizontal. if the initial velocity is 830m/s, find how high the projectile is launched?

give clear steps

4900 m

Explanation:

Given, in the y direction:

v₀ = 830 sin 22° m/s ≈ 311 m/s

v = 0 m/s

a = -9.8 m/s²

Find: Δy

v² = v₀² + 2aΔy

(0 m/s)² = (311 m/s)² + 2 (-9.8 m/s²) Δy

Δy ≈ 4930 m

Rounded to two significant figures, the vertical displacement is 4900 m.

some think that theories become laws, but theories and laws have separate and distinct roles in the scientific method. a law is a description of an observed phenomenon in the natural world that hold true every time it is tested. it doesn't explain why something is true; it just states that it is true.

mark brainliest i am trying to get to the next level!

i will be your freind and say    

that tool is called an altimeter which measures your altitude which can be used to tell which atmosphere you are currently in, including the stratosphere.

hope this ! : )