A2.0-kg projectile moves from its initial position to a point that is displaced 20 m horizontally and 15 m above its initial position. how much work is done by the gravitational force on the projectile

W= - 300 J

Explanation:

Given that

Mass ,m= 2 kg

Horizontal distance ,x= 20 m

Vertical distance ,y= 15 m

As we know that gravity force always acts in the downward direction

F= m g

The displacement of the object is in upward direction

d= -15 m

The work done by a force given as

W= F.d

Now by putting the values

W= - 2 x 10 x 15                ( Take g= 10 m/s²)

W= - 20 x 15

W= - 300 J

Therefore the work done by gravitational force will be -300 J.

the total distance traveled by the car is

30km + 49km = 79 km .

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s