Acar with mass 1600 kg drives around a flat circular track of radius 28.0 m. the coefficient of friction between the car tires and the track is 0.830. the car is traveling at the maximum speed possible without losing traction.

v=15.24 m/s

Explanation:

Given that

Mass ,m= 1600 kg

radius ,r= 28 m

Coefficient of friction ,μ = 0.83

The radial force on the car when it takes turn

The friction force on the car

Fr= μ m g

The condition for motion without losing traction

F= Fr

v²=μ r g

Now by putting the values

 ( take g=10m/s²)

v=15.24 m/s

The speed of the car will be 15.24 m/s

magnified images possible images can be real = projected onto a screen

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s