At a certain time a particle had a speed of 18 m/s in the positive x direction, and 2.4 s later its speed was 30 m/s in the opposite direction. what is the average acceleration of the particle during this 2.4 s interval?

Explanation:

We have equation of motion v = u + at

     Initial velocity, u =  18 m/s

     Final velocity, v =  -30 m/s    

     Time, t = 2.4 s

     Substituting

                      v = u + at  

                      -30 = 18 + a x 2.4

                      a = -20 m/s²

     Acceleration is -20 m/s²

Average acceleration of the particle during the 2.4 s interval is -20 m/s²

answer: the rock sample is a sedimentary rock.

explanation:

it is given that:

mass of rock sample, m = 2.7 g

volume of rock sample,

so, density of rock sample will be

since, the density of rock sample is . hence, the rock sample is a sedimentary rock, whose densities varies between .

a electromagnetic waves