In an lc circuit at one time the charge stored by the capacitor is 10 mc and the current is 3.0 a. if the frequency of the circuit is (1/(4.0)) khz, when the charge stored is 6.0 mc, what is the current?

Explanation:

LC Circuit

It's a special circuit made of three basic elements: The AC source, a capacitor, and an inductor. The charge, current, and voltage are oscillating when there is an interaction between the electric and magnetic fields of the elements. The following variables will be used for the formulas:

= charge of the capacitor in any time

= initial charge of the capacitor

=angular frequency of the circuit

= current through the circuit in any time

The charge in an LC circuit is given by

The current is the derivative of the charge

We are given

It means that

From eq 1:

From eq 2:

Squaring and adding the last two equations, and knowing that

Operating

Solving for

Now we know the value of , we repeat the procedure of eq 1 and eq 2, but now at the second time , and solve for

Solving for

Now we replace the given values. We'll assume that the placeholder is a pi for the frequency, i.e.

Finally

what are the statements? x