Agoldfish is swimming at 3.20 cm/stoward the front wall of a rectangular aquarium. what is theapparent speed of the fish as measured by an observer looking infrom outside the front wall of the tank? the index of refraction ofwater is 1.333

0.024m/s

Explanation:

Firstly, we have to convert the 3.20cm/s to m/s which is done by dividing the 3.20 by 100. the answer gives 0.032m/s. Then using the formular v=c/n where v is the apparent speed, c = speed of object and n is the refractive index of medium.we can now solve using the above formular which is 0.032m/s/1.333 = 0.024m/s

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