12) the small piston of a hydraulic lift has a diameter of 8.0 cm, and its large piston has a diameter of 40 cm. the lift raises a load of 15,000 n. (a) determine the force that must be applied to the small piston. (b) determine the pressure applied to the fluid in the lift.

600 N

119366.20731 Pa

Explanation:

= Force on the smaller piston

= Area of the smaller piston =

= Force on the larger piston = 15000 N

= Area of the larger piston =

From Pascal's law we have

The force that must be applied to the small piston is 600 N

Pressure would be

The pressure applied to the fluid in the lift is 119366.20731 Pa

the amount of current in the coil

less than one you can't create energy