An 81.5-kg man stands on a horizontal surface.

(a) what is the volume of the man's body if his average density is 985 kg/m^3?
(b) what average pressure from his weight is exerted on the horizontal surface if the man's two feet have a combined area of 4.50 × 10-2 m^2.

a)V= 0.0827 m³

b)P=181.11 x 10²  N/m²

Explanation:

Given that

m = 81.5 kg

Density ,ρ = 985 kg/m³

As we know that

Mass = Volume x Density

81.5 = V x 985

V= 0.0827 m³

The force exerted by weight = m g

 F= m g= 81.5 x 10 = 815 N      ( Take ,g= 10 m/s²)

Area ,A= 4.5 x 10⁻² m²

The Pressure P

P=181.11 x 10²  N/m²

car a and b are moving in opposite directions

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