Runner a is initially 6.0 mi west of a flagpole and is running with a constant velocity of 5.0 mi/h due east. runner b is initially 9.0 mi east of the flagpole and is running with a constant velocity of 8.0 mi/h due west. how far are the runners from the flagpole when they meet?

0.2 mi west of the flag pole.

Explanation:

distance of runner A from pole = 6 mi east

velocity of runner A = 5 mi/h

distance of runner B from pole = 9 mi east

velocity of runner B = 8 mi/h

total distance = 9 + 6 = 15 mi

How far are the runners from the flagpole when they meet?

lets assume the time at which they both meet be T hours

        the distance covered by runner A = speed x time = 5 x T = 5T

        the distance covered by runner B = speed x time = 8 x T = 8T

       distance by runner A + distance by runner B = 15 miles

       5T + 8T = 15

       13T = 15

        T = 1.15 hours

        distance covered by runner A = 5T = 5 x 1.15 = 5.8 mi

        distance covered by runner B = 8T = 8 x 1.15 = 9.2 mi

        runner A is 5.8 mi east of his starting point

        runner B is 9.2 mi west of his starting point

        (all can be seen from the attached diagram)

        from runner A ⇒ 6 - 5.8 = 0.2 mi west of the flag pole.

          or

        from runner B ⇒ 9 - 9.2 = -0.2 = 0.2 mi west of the flag pole

be subject to a force andchange its motion

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