Probabilities and energies in quantum dots (15 points) quantum dots are nanoscale semiconductor devices that can be used in a variety of applications, including transistors and solar cells. consider an electron trapped in a quantum dot, which we will model as a one-dimensional, rigid-walled box of length 0.900 nm. let x=0 be the left side of the box

(a) what is the probability of finding the electron between x1 = 0.260 nm and x2 = 0.640 nm for the n= 1 state? (give your answer as a decimal between 0 and 1.)
(b) repeat part (a) for the n=2 state.
(c) what is the energy of the quantum dot system in electron volts if it is in the n= 1 state
(d) repeat part (c) for the n=2 state.
(e) what photon energy in ev) is emitted by the quantum dot if it transitions from the n= 2 to n= 1 state?

answer: the correct answer id option(d).

explanation:

snell's law refraction:

the angle of refraction =

the angle of incidence =

refractive index of air = = 1

refractive index of glycerol = 1.47

from the given options, the most closest answer to 63.72° is 65° of option (d).

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂