2.65 in a standard tensile test a steel rod of 22-mm diameter is subjected to a tension force of 75 kn. knowing that n 5 0.30 and e 5 200 gpa, determine (a) the elongation of the rod in a 200-mm gage length, (b) the change in diameter of the rod.

To solve this problem it is necessary to apply the concepts related to uniaxial deflection for which the training variable is applied, determined as

Where,

P = Tensile Force

L= Length

A = Cross sectional Area

E = Young's modulus

PART A) The elongation of the bar in a length of 200 mm caliber, could be determined through the previous equation, then

Therefore the elongaton of the rod in a 200mm gage length is

PART B) To know the change in the diameter, we apply the similar ratio of the change in length for which,

Where,

Poission's ratio

= Lateral strain

= Linear strain

Therefore the change in diameter of the rod is

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explanation:

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