Atire placed on a balancing machine in a service station starts from rest and turns through 4.0 rev in 1.0 s before reaching its final angular speed. assuming that the angular acceleration of the wheel is constant, calculate the wheel’s angular acceleration. answer in units of rad/s 2 .

a  = 50.26 rad/s^2

Explanation:

We know that:

θ =

where θ is the angle, a the angular aceleration and t the time.

First, we need to find how many rad are equivalent to 4 rev, as:

θ = 4 rev * 2π = 25.13 rad

Finally, replacing θ by 25.13 rad and t by 1 second, we get:

25.13 rad =

Solving for a:

a  = 50.26 rad/s^2

u=13

v=30

s/t=u+1\2at

=13+431/2

=13+265.5

=278.5

if they have a finite resultant