Ajet moving at 500.0 km/ h due is in a region where the wind is moving at 120.0 km/h in a direction 30.00° north of east. what is the speed of the aircraft relative to the ground?

The speed of the aircraft relative to the ground is 606.9

Explanation:

x-y coordinate system:  

x is Positive due East direction. Similarly  y is Positive due North Direction.

Now let us Decompose each vector into x-y

500 km/h due east = (500, 0)

120 km/h at 30 degree north of east

=

=

=

Adding  the vectors.

=

=

=

=

= (603.8, 60)

Returning back to polar form

Magnitude =

explanation:

v=uf/(u-f)

= 5.-10/(5+10) convex lens has negative focal length