The specific heat of fat is roughly 1,700 j/(kgoc) whereas that for water is around 4200 j/(kgoc). a 0.63 kg solution of lipids and water is heated at a rate of 100 w for 5 minutes. during this time, the temperature of the system increases by 20oc. what is the mass of the lipid content, to the nearest hundredth of a kg, in this solution?

the mass of the lipid content, to the nearest hundredth of a kg, in this solution =0.46 kg

Explanation:

Total heat content of the fat = heat content of water +heat content of the lipids

Let it be Q

the Q= (mcΔT)_lipids + (mcΔT)_water

total mass of fat  M= 0.63 Kg

Q= heat supplied = 100 W in 5 minutes

ΔT= 20°C

c_lipid= 1700J/(kgoC)

c_water= 4200J/(kgoC)

then,

solving the above equation we get

m= 0.46 kg

the mass of the lipid content, to the nearest hundredth of a kg, in this solution =0.46 kg

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2