Three identical particles, q1, q2, and q3, each with charge q = 5.00 μc, are placed along a circle of radius r = 2.00 m at angles 90, 180, and 270 degrees from the positive x-axis, respectively.
what is the resultant electric field at the center of the circle, point o? all angles are measured counterclockwise from the positive x-axis.

11250 N/C

Direction: 0 deg counterclockwise from positive x-axis

Explanation:

= magnitude of charge on each particle = 5 μC =  5 x 10⁻⁶ C

= distance of each particle from center of circle = 2 m

= Magnitude of electric field at the center by each particle

Magnitude of electric field at the center by each particle is given as

inserting the values

From the diagram , we see that being equal and opposite, the electric fields due to charge q₁ and q₃ cancel out.

So net electric field at center is only due to charge q₂ direction towards positive x-direction

So

= Resultant electric field = 11250 N/C

Direction: 0 deg counterclockwise from positive x-axis

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.