A.005kg projectile leaves a 1500kg launcher with a velocity of 750 m/s. what is the recoil velocity of the projectile

The recoil velocity of the projectile is 0.0025m/s

Explanation:

Given:

Mass of the projectile =0.005kg

Mass of the launcher = 1500kg

Velocity =  750 m/s.

To Find:

The recoil velocity of the projectile = ?

Solution:

The recoil velocity is the obtained by dividing the "recoil momentum"  by the "mass of the recoil body".  The recoil momentum is equal to the momentum of the other body. The momentum of the other body is equal to it mass times its velocity.

Lets find the recoil momentum,

Recoil momentum = mass of the projectile X velocity

Recoil momentum =

Recoil momentum = 3.75

Now Recoil Velocity,

Recoil Velocity =

Recoil Velocity =

Recoil Velocity = 0.0025m/s

where’s the list ? the question is incomplete

305.7

explanation:

density =m/v

density =917/3.00

density = 305.

approximately = 305.7

in four significant figures