Asatellite is in a circular orbit around the earth at an altitude of 2.30 106 m. (a) find the period of the orbit. 2.23 correct: your answer is correct. h (b) find the speed of the satellite. 6.78 correct: your answer is correct. km/s (c) find the acceleration of the satellite. 5.3 correct: your answer is correct. m/s2 toward the center of the earth need ? read it

(a) T = 2.23h

(b) v = 6.78 km/s

(c) a = 5.31 m/s²

Explanation:

(a) The period (T) of the orbit can be calculated using Kepler's Third Law equation:

   (1)  

where r: is the distance from the center of the Earth and the satellite, G: is the gravitational constant = 6.67x10⁻¹¹m³kg⁻¹s⁻² and M: is the Earth's mass = 5.97x10²⁴kg

Since

where : is the Earth's radius and : is the distance between the surface of the Earth and the satellite

Hence, by entering the radius calculated into equation (1) we can find the period of the orbit:

(b) The speed (v) of the satellite can be calculated using the following equation:

(c) The acceleration (a) of the satellite is:

I hope it helps you!

at positions a, g kinetic energy is maximum.

at position d, potential energy is maximum.

its c i just checked it