Apatient is given 40.00 mg of iodine-131 (131i ) 131 53
the half-life of 53 i is 8 days.
how many milligrams of the 131i remains in the
patient after 32 days?

2.5 mg

We are given;

We are required to determine the mass that will remain;

N = N₀ × 0.5^n

where, N is the remaining mass, N₀ is the original mass, and n is the number of half lives.

Therefore;

n = time ÷ half life

   = 32 days ÷ 8 days

  = 4

Therefore;

Remaining mass = 40.0 mg × 0.5^4

                            = 2.5 mg

Hence, the remaining mass of I-131 after 32 days is 2.5 mg

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