Aspace station in the form of a large wheel, 283 m in diameter, rotates to provide an "artif icial gravity" of 9.5 m/s 2 for people located at the outer rim. what is the frequency of the rotational motion for the wheel to produce this effect? answer in units of rev/min.

The frequency of the rotational motion for the wheel to produce this effect is 2.473 rev/min.

Explanation:

Given that,

Acceleration = 9.5 m/s²

Diameter = 283 m

We need to calculate the frequency of the rotational motion for the wheel to produce this effect

Using formula of rotational frequency

Where, r = radius

a = acceleration

= rotational frequency

Put the value into the formula

The frequency in rev/min

Hence, The frequency of the rotational motion for the wheel to produce this effect is 2.473 rev/min.

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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