Asubmarine is stranded on the bottom of the ocean with its hatch 25 m below the surface. in this problem, assume the density of sea water is 1.03 × 103 kg/m3. show answer no attempt calculate the force, in newtons, needed to open the hatch from the inside, given it is circular and 0.25 m in diameter. the air pressure inside the submarine is 1.00 atm.

F = 49.55 x 10 ³ N

Explanation:

Given :

ρ = 1.03 x 10³ kg / m³ ,  h= 25 m , g = 9.8 m / s² , r = 0.25 m

So solve to determine force

A = π * r² = π * (0.25 m)²

A = 196.34 x 10 ⁻³ m²

The pressure of the water

P = F / A

Determine the force using the pressure into the area

F = P * A

P = ρ * g * h

Replacing numeric

P = 1.03 x 10³ kg / m³ * 9.8 m / s² * 25 m

P = 252.35 x 10³ N / m²

F = P * A  ⇒ F = 252.35 x 10³ N / m²  * 196.34 x 10 ⁻³ m²  

F = 49.55 x 10 ³ N

seeing the graph would

unbalanced force

explanation: