Problem page gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . suppose 28. g of ethane is mixed with 190. g of oxygen. calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. round your answer to significant digits. clears your work. undoes your last action. provides information about entering answers. g

Answer : The maximum mass of carbon dioxide produced by the chemical reaction can be, 82.3 grams.

Solution : Given,

Mass of = 28 g

Mass of = 190 g

Molar mass of = 32 g/mole

Molar mass of = 30 g/mole

Molar mass of = 44 g/mole

First we have to calculate the moles of and .

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

From the balanced reaction we conclude that

As, 2 mole of react with 7 mole of

So, 0.933 moles of react with moles of

From this we conclude that, is an excess reagent because the given moles are greater than the required moles and is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of

From the reaction, we conclude that

As, 2 mole of react to give 4 mole of

So, 0.933 moles of react to give moles of

Now we have to calculate the mass of

Therefore, the maximum mass of carbon dioxide produced by the chemical reaction can be, 82.3 grams.

get the total number of pieces of fruit and divide it by 4 to get the average. the result is the answer to the problem. 14 total number of fruits and there are 4 members. 14 divided by 4 is equals to 3.5.

the old price per ounce is c/4.

the new price per ounce is c/3.6.

the ratio of the old price to the new one is

(c/4)/(c/3.6) = (c/c)×(3.6/4) = 0.9 . . = 9/10 . . "nine tenths" in either form