What is the maximum speed at which a car can safely travel around a circular track of radius 55.0 m if the coefficient of friction between the tire and
road is 0.3502
2.60 m/s
4.39 m/s
13.7 m/s
43.0 m/s

The maximum speed of the car should be 13.7 m/s

Explanation:

For the car to travel at a maximum safe speed , the frictional force acting should be maximum and at the same time should provide the necessary centripetal force.

Let 'k' (=0.3502) be the coefficient of friction and 'N' be the normal force acting on the surface.

Then ,

N = mg , where 'm' is the mass of the body and 'g'(=9.8) is the acceleration due to gravity.

∴ Maximum frictional force , f = kN = kmg

Centripetal force that should act on the car to move with maximum possible speed is -

 , where 'v' is the velocity of the car and 'r'(=55m) is the radius of circular path.

Equating the 2 forces , we get -

∴

Substituting all the values , we get -

v = 13.7 m/s.

when jerome paddle in flowing river towards east the net speed of jerome will increase

so the net speed of jerome will be given as

now the speed of paul will be same as it is given as he is running on the ground

so

so here we can say since the speed of jerome is more so he will win the race

now as we know the distance so the time difference is given as

so jerome will reach first and the time difference will be 203.55 s or 3.4 min