An 1100 kg trailer is hitched to a 3200 kg car. the car and trailer are traveling at 60 km/h when the driver applies the brakes on both the car and trailer.

knowing that the braking forces exerted on the car and the trailer are 3700 n and 800 n respectively, determine

(a) the distance traveled [m] by the car and trailer before they come to stop,

(b) the horizontal component of the force [n] exerted by trailer hitch onto the car.

(a). The distance traveled by the car and trailer before they come to stop is 132.32 m

(b). The horizontal component of the force [N] exerted by trailer hitch onto the car is 2560 N.

Explanation:

Given that,

Mass of trailer = 1100 kg

Mass of car = 3200 kg

Speed of car and trailer = 60 km/h =16.67 m/s

Braking force on the car= 3700 N

Braking force on the trailer = 800 N

We need to calculate the acceleration

Using formula of acceleration

Where, F = total force

m = total mass

Put the value into the formula

(a). We need to calculate the distance traveled by the car and trailer before they come to stop

Using equation of motion

Put the value into the formula

(b). We need to calculate the horizontal component of the force exerted by trailer hitch onto the car

Firstly, we need to calculate the average braking force

Put the value into the formula

We need to calculate the net force on hitch

Hence, (a). The distance traveled by the car and trailer before they come to stop is 132.32 m

(b). The horizontal component of the force [N] exerted by trailer hitch onto the car is 2560 N.

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