How thick a layer would earth form as it wraps around the neutron star’s surface? assume that the layer formed by earth has the same average density as the neutron star. (hint: consider the mass of earth to be distributed in a spherical shell over the surface of the neutron star and then calculate the thickness of such a shell with the same mass as earth. the volume of a spherical shell is approximately its surface area times its thickness: vshell=4πr2×thickness. because the shell will be thin, you can assume that its radius is the radius of the neutron star.)

Explanation:

Let the radius of the neutron star be R.

Its surface ares a will be 4πR² . Let the thickness required be t .

The volume of the envelop  of  thick shell

4πR² t .This must be the volume of the sphere

= 4/3 πR³

mass = 4/3 πR³ ρ where  ρ is the density of the star.  ρ will also be density of shell's envelop. So mass of envelop

= 4πR² t .

Given that

mass of envelop  = mass of the earth

4πR² t ρ =  4/3 πR³ ρ

R = 3t

elctricity and magnet is conversion to it

can u provide the graph and if its not possible

then i can tell u the segment where the

average time interval starts degrading is the segment where the car is slowing down