Problems like this a diver bounces straight up from a diving board, avoiding the diving board on the way down, and falls feet first into a pool. she starts with a velocity of 3.00 m/s, and her takeoff point is 1.80 m above the pool.

This question is incomplete the complete question is

A diver bounces straight up from a diving board, avoiding the diving board on the way down, and falls feet first into a pool. She starts with a velocity of 4.00 m/s and her takeoff point is 1.80 m above the pool. (a) What is her highest point above the board? (b) How long a time are her feet in the air? (c) What is her velocity when her feet hit the water?

(a) Xs=0.459m

(b) t=0.984 s

(c) Vc=6.65 m/s

Explanation:

(a) To reach maximum distance

(b) For Time

To find t we must find t1 and t2

as

t=t1+t2

For T1

For T2

For Total Time

t=t1+t2

t=0.306+0.6789

t=0.984s

(c) To find Vc

Vc=Vb+gt2

Vc=(0)+(9.8)(0.6789)

Vc=6.65 m/s

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the rearrangement of particles in a physical change. hope this