A1423-kg car is moving along a level highway with a speed of 26.4 m/s. the driver takes the foot off the accelerator and the car experiences a slowing force of 901-n over a distance of 106 m. determine the speed of the car after traveling this distance.

Final speed, v = 28.81 m/s

Explanation:

Given that,

Mass of the car, m = 1423 kg

Initial speed of the car, u = 26.4 m/s

Force experience by the car, F = 901 N

Distance, d = 106 m

To find,

The speed of the car after traveling this distance.

Solution,

The force experienced by a car is equal to the product of mass and acceleration.

Let v is the final speed of the car. Using third equation of motion to find it as :

v = 28.81 m/s

So, the final speed of the car is 28.81 m/s.

force required to detach it is given by

charges are taken to be fundamental charge

now we have

so above is the minimum distance at which it will detach

answer: 31, 5556. 952 seconds