Any for the questions will be great

1) The mass of the skier, m = 51.02 kg

2) At top of the hill, v = 0

3) The velocity of the skier at the 30 m height, v = 37.04 m/s

4)  The velocity of the skier at the bottom of the hill, v = 44.27 m/s

Explanation:

Given data,

The initial height of the skier from the ground, h = 100 m

The K.E of skier at 100 m = 0 J

The P.E of the skier at 100 m = 50,000 J

1) The mass of the skier,

                          m = P.E/ gh

                              = 50,000/ (9,8 x 100)

                              = 51.02 kg

2) The velocity of the skier at the top of the hill,

At top of the hill, the K.E = 0,

Hence,

                             v = 0

3) The velocity of the skier at the 30 m height,

                            P.E = mgh

                                  = 51.02 x 9.8 x 30

                                   = 14,999.88 J

                            E = P.E + K.E

                            K.E = E - P.E

                                   = 50,000 - 14,999.88

                                    = 35000.12 J

                              v = √(2 K.E/m)

                                 = √(2 x 35000.12 / 51.02)

                              v = 37.04 m/s

4) The velocity of the skier at the bottom of the hill,

At bottom of the hill, P.E = 0 and K.E is maximum

                                  K.E = 50,000 J

                                  v = √(2 K.E/m)

                                     = √(2 x 50000 / 51.02)

                                  v = 44.27 m/s

the temperature in kelvin of 2.0 dm3 of an ideal gas is doubled and its pressure is increased by a factor of four. what is the final volume of the gas