A1500-kg car locks its brakes and skids to a stop on a slippery horizontal road, leaving skid marks that are 15 m long. how much mechanical energy was dissipated as this happened? the coefficient of kinetic friction between the tires and the road is 400.40un.

Explanation:

Given:

So, the energy dissipated during the skidding of car:

Frictional force:

where N = normal reaction by ground on the car

Now from the work-energy equivalence:

is the dissipated energy.

u=13

v=30

s/t=u+1\2at

=13+431/2

=13+265.5

=278.5

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.