Physics, 13.12.2019 05:31 machucajazz34182

Aboat begins at point a and heads straight across a 60-meter wide river with a speed of 4 m/s (relative to the water). the river water flows north at a speed of 3 m/s (relative to the shore). the boat reaches the opposite shore at point c. which would cause the boat to reach the opposite shore at a location south of c?

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Answer from: gracekerleyy

The river should flow north at 2 m/s and the boat with a speed of 5 m/s

Explanation:

The question is incomplete, but, here are the options:

a) river flows north at 2 m/s

b) river flows north at 4 m/s

c) boat heads across with 5 m/s

d) boat heads across with 4 m/s

Now to answer this, look on the picture attached. As you can see point C is in a diagonal direction from A, therefore, the boat is not crossing the river in a straight line, because of the speed of the river flow.

The direction is heading is like a triangle (See picture), so, if we know the speed of the boat in a straight line which is 4 m/s and the speed of river which is 3 m/s, we can know the speed in the diagonal direction, using the following expression:

V = √Vx² + Vy²

Now, we want a location south of C, but it's the same, because looking the picture, you can actually see that it's not going to poinnt B, just a little south from C. We still have the x and y components, which is the speed of the boat and the river, therefore replacing in the above equation:

V = √4² + 3²

V = 5 m/s

This is the speed which the boat needs to cross the river to reach a point south of C.

Now, the river is exerting something here too. All we need to do, is see the difference of the 2 speeds, and then, substract than from the speed of the flow. This has logic, because is the speed of the river is lower and the speed of boat is higher, he can reach a point at C in the south still so:

V = 4 -3 = 1 m/s

Vriver = 3 - 1 = 2 m/s

Answer from: Quest

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge, $v = \dfrac{e_p}{q}$ then the following gives us the potential difference, $\delta v = v_b - v_a$ $\begin{aligned} \delta v & = \dfrac{e_p_b}{q} - \dfrac{e_p_a}{q} \\ & = \dfrac{\delta e_p}{q} \end{aligned}$ the formula $\delta v = \delta e_p / q$ may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get $\delta e_p = q\delta v$ using q = 8.00 × 10⁻¹⁹ c and δv = 2.00 v, we get $\begin{aligned} \delta e_p & = (8.00\times10^{-19} \text{ c})(2.00\text{ v}) \\ & = 1.60\times 10^{-18}\text{ j} \end{aligned}$ the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.

Answer from: Quest

Answerigneous bedrock of the oceanic crust;

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Aboat begins at point a and heads straight across a 60-meter wide river with a speed of 4 m/s (relat...

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