Asteel section of the alaskan pipeline had a length of 56.5 m and a temperature of 24.7 °c when it was installed. what is its change in length when the temperature drops to a frigid -43.1 °c?

Change in length=0.0275 m.

Explanation:

Given that

Length L= 56.5 m

Initial temperature ,T₁ = 24.7⁰C

Final temperature ,T₂ = -43.1 ⁰C

Coefficient of thermal expansion for steel taken as

α = 7.2 x 10⁻⁶ /⁰C

We know that change in the length due to change in the temperature given as

ΔL = Lα  ΔT

ΔL =56.5 x 7.2 x 10⁻⁶ x (-43.1 -24.7 ) m

ΔL = - 27581.04 x 10⁻⁶ m

ΔL = -0.0275 m

Therefore the length of the steel get reduce by 0.0275 m.

The change in the length will be 0.0275 m.

i think it because equal matrices have equal dimensions, only square matrices can be symmetric. for all indices and . every square diagonal matrix is symmetric, since all off-diagonal elements are zero. in linear algebra, a real symmetric matrix represents a self-adjoint operator over a real inner product space.