For the acetone(1)/methanol(2) system, a vapor mixture for which z1 = 0.25 and z2 = 0.75 is cooled to temperature t in the two-phase region and flows into a separation chamber at a pressure of 1 bar. if the composition of the liquid product is to be x1 = 0.175, what is the required value of t and what is the value of y1? for liquid mixtures of this system, to a good approximation,

Distance covered = speed x timethe distance traveled going against the stream = distance traveled with the stream.therefore it is the speed and the time that are the variables.as he travels the same distance both ways, speed x time is the same for each way.going upstream his speed is 4 kph; going downstream his speed is 6 kph.therefore we have two simultaneous equations: time upstream x 4 = time downstream x 6time upstream + time downstream = 60 minutestherefore we have the equation: time upstream = 6/10 hour, time downstream therefore = 4/10 hour.distance traveled at 4km/hr in 6/10 hour = 24/10 = 2.4km.check: distance traveled at 6km/hr in 4/10 hour = 24/10 = 2.4km.