An electromagnet produces a magnetic field of 0.530 t in a cylindrical region of radius 2.80 cm between its poles. a straight wire carrying a current of 10.7 a passes through the center of this region and is perpendicular to both the axis of the cylindrical region and the magnetic field. what magnitude of force does this field exert on the wire?

Magnetic force, F = 0.317 N

Explanation:

Given that,

Magnetic field produced by an electromagnet, B = 0.53 T

Radius of the electromagnet, r = 2.8 cm = 0.028 m

Current, I = 10.7 A

Let F is the magnitude of force this field exert on the wire. Its formula is given by :

Here,

(L = 2r)

F = 0.317 N

So, the magnitude of force the field exert on the wire is 0.317 N. Hence, this is the required solution.

the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

elctricity and magnet is conversion to it