Amodel rocket with a mass of 0.212 kg is launched into the air with an initial speed of 84 m/s. how much kinetic energy will the rocket have at a height of 214 m? assume there is no wind resistance.
444 j

747 j

303 j

634 j

Option C

303 J

Explanation:

Energy can neither be created nor destroyed but only transformed from one state to the other.

Initial

Initial potential energy=mgh but since h=0 then energy is 0

Final potential energy=mgh=0.212*9.81*214=445.06008  J

Considering that initial energy is 747.936+0=747.936 J, final energy should also be the same. The final kinetic energy is the difference between total sum of energy and potential energy

f=gm1m2/d^2 it d

f is force g is gravitaiton constant, m1 is mass of first object, m2 is mass of second object. d is distance between two object

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