Asphere of plastic of radius = .100 m is completely immersed in water. the density of the plastic is 600 kg/m3. since the plastic would otherwise float it is restrained from moving upward by a thread attached to the bottom of the container. what is the tension in the thread?

To solve this problem we need to use the proportional relationships between density, mass and volume, together with Newton's second law.

The force can be described as

Where,

m = Mass

g = Gravitational acceleration

At the same time the Density can be defined as

Where,

m = mass

V = Volume

Replacing the value of the mass at the equation of Force we have,

Since the difference between the two forces gives us the total Force then we have to

Where

Force of the water

= Force of plastic

Therefore with the values for this force we have,

Therefore the tension in the thread is 16.412N

a straight line sloped

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards