An exoplanet is in an elliptical orbit around a distant star. at its closest approach, the exoplanet is 0.540 au from the star and has a speed of 54.0 km/s. when the exoplanet is at its farthest distance from the star of 41.0 au, what is its speed (in km/s)? (1 au is the average distance from the earth to the sun and is equal to 1.496 ✕ 1011 m. you may assume that other planets and smaller objects in the star system exert negligible forces on the exoplanet.)

0.71121 km/s

Explanation:

= Velocity of planet initially = 54 km/s

= Distance from star = 0.54 AU

= Final velocity of planet

= Final distance from star = 41 AU

As the angular momentum of the system is conserved

When the exoplanet is at its farthest distance from the star the speed is 0.71121 km/s.

two charges are fixed in place on the x-axis as shown. the charge at x = 0 is negative and has magnitude q = 2 μcoulombs (1 μcoulomb = 10-6 coulombs). the charge at x = d, (d = +12 cm), is positive and has magnitude q = 4 μcoulombs. find a point x = xo along the x-axis at which the electric field is zero.

answer: d. a cme increases the amount of energy in the solar wind

explanation:

coronal mass ejections, also called cmes, are large clouds of plasma and magnetic field that erupt from the sun. only when the cloud is aimed at earth will the cme hit earth and therefore cause impacts. high-speed solar wind streams come from areas on the sun known as coronal holes.