An astronaut landed on a far away planet that has a sea of water. to determine the gravitational acceleration on the planet's surface, the astronaut lowered a pressure gauge into the sea to a depth of 24.3 m. if the gauge pressure is measured to be 3.8 atm, what is the gravitational acceleration on the planet's surface?

Acceleration due to gravity will be

Explanation:

We have given gauge pressure P = 3.8 atm = 3.8×101325 = 385035 Pa

Depth h = 24.3 m

Density

We have find the acceleration due to gravity at the surface of planet

We know that pressure is given by

So

Acceleration due to gravity will be

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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i think if it were me i whould divide 300 dide 15

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