In an evaporation of water experiment, the initial mass of water in a beaker was 10.5775 +/- 0.0002 g. after some time, the mass of the water in the beaker was 10.3005 +/- 0.0002 g. the mass evaporated is calculated by subtracting the final mass from the initial mass. what is the final propagated error on the evaporated mass?

Explanation:

The theory of  propagation of error in case of addition and subtraction states that maximum errors are added in absolute terms in both the operation of addition and subtraction . So in this case the subtracted value will be

10.5775 - 10.3005

= .2770 g

errors will be added ie in subtracted value we can find error to the tune of

.0002 + .0002 = .0004 g

So the subtracted value will be written as

.2770 ± .0004

explanation:

a fuel engine ( known as a gasoline engine in american english )is an internal combustion engine with spark ignition, designed to run on petrol (gasoline) and similar volatile fuels.