Consider the following 4 cases of motion of the same mass under a constant downward gravitational acceleration g = 9.8 m/s 2 . a b c h θ α d d o b a c v v v vo v v in cases a & b the mass is released from rest. in cases c & d the initial speeds are v0. in all 4 cases the mass fell the same distance h. calculate the final speed va of the mass.

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-the future of geothermal energy can pretty much be summed up with a single word: more

-scientists plan in going deeper than 120 meters

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d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day

force tends to be low and long diustance masses are high