Two object accumulated a charge of 4.5 μc and another a charge of 2. 8 μc. these two objects are separated by a distance of 2.5 cm. calculate the magnitude of the electric force between these two objects.

181.23 C

Explanation:

According to Coulomb's Law:

Where:

 is the electrostatic force

is the Coulomb's constant  

is the charge of object 1

is the charge of object 2

is the separation distance between the charges

layers of the earth affect the waves and these effects are seen on instruiments such as seimometers

speed of light in vacuum is 300,000 km/s

speed of light in other mediums is given by the expression v = c/n, where c is the speed of light in vacuum and n is the refractive index of medium.

for the first medium v = 200,000 km/s

  so, refractive index of medium = 300000/200000 = 1.5

    1.5 refractive index is usually for glass. so first medium is glass.

for the second medium v = 250,00 km/s

so, refractive index of medium = 300000/250000 = 1.2

    1.2 refractive index is usually for water. so second medium is water.

for the third medium v = 0 km/s

so, refractive index of medium = 300000/0 = ∞

    ∞ refractive index is usually for opaque mediums. so third medium is opaque medium.