If it requires 5.0 j of work to stretch a particular spring by 2.2 cm from its equilibrium length, how much more work will be required to stretch it an additional 3.6 cm ?

Explanation:

Fist we must find the constant of the spring. The equation for work in a spring is:

where , is the work, in this case , is the constant of the spring, and is the distance from the equilibrium length:

clearing for and substituting known values:

So work to stretch the spring, an additional 3.6cm is:

where

And since we already have 5J, the difference, or the additional work is:

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards