Atreasure hunter following a secret map
walks 13.8 km at 35.3° north of west to an old
tree stump, then turns and goes 17.6 km at
60.6° south of east to a large rock. find the
treasure hunter's final displacement.

answer:

19.02km

explanation:

as we apply head to tail rule suppose the man is at a walks upto b and then to c. we can find the direct path from a to c.

ac= ab+bc

but f=√fₓ² +fy²

fₓ= fcos ∅⇒ 13.8 cos 35.3= 11.26

fy= fsin∅⇒17.6 sin 60.6=15.33

f=√126.79+235.01=√361.7989= 19.02 km

fgravity=10x10=100n case 1

fgravity=30x20=600n case 2

6 times more

beta is electron from nucleus

something from nucleus has changed, but charge must be same for cons of charge