Arectangular loop (area = 0.15 m2) turns in a uniform magnetic field, b = 0.18 t. when the angle between the field and the normal to the plane of the loop is π/2 rad and increasing at 0.75 rad/s, what emf is induced in the loop?

Emf induced in the loop is 0.02V

Explanation:

To get the emf of induced loop, we have to use faraday's law

ε = - dΦ/dt

To get the flux, we use;

Φ = BA cos(θ)

B = The uniform magnetic field

A = Area of rectangular loop

θ = angle between magnetic field and normal to the plane of loop

substitute the flux equation (Φ) into the faraday's equation

we have ε = - d(BA cos(θ)) / dt

ε = BA sinθ dθ/dt

from the question;B = 0.18T, A=0.15m2, θ = π/2 ,dθ/dt = 0.75rad/s

Our equation will now look like this;

ε = (0.18T) (0.15m2) (sin(π/2)) (0.75rad/s)

ε = 0.02V

force required to detach it is given by

charges are taken to be fundamental charge

now we have

so above is the minimum distance at which it will detach