Aball with an initial velocity of 25 m/s is subject to an acceleration of -9.8m/s^2 how high does it go before coming to a momentary stop ?

The ball will reach an height of 31.88 meters before coming to a stop.

Explanation:

we know that by equation of motion

where v is the final velocity of the ball , u is the initial velocity of the ball , a is acceleration due to gravity and s is the distance traveled by the ball.

a = -9.8

and u = 25 m/s

and v = 0

therefore s =

so s = 31.88 meters

hi there!

out of the two, (b) precision would be more reasonable.   however, both a and b could be pretty reasonable.

-awesomerepublic   : )

molecules are free to separate from each other and will take on the shape of the container. molecules move completely at random and high speeds. they vibrate in a fixed position and do not move around much. molecules expand to the edge of their container.