A1.80-kg monkey wrench is pivoted 0.250 m from its center of mass and allowed to swing as a physical pendulum. the period for small-angle oscillations is 0.940 s.

Moment of inertia,

Explanation:

It is given that,

Mass of the monkey, m = 1.8 kg

Distance from the center of mass, d = 0.25 m

The time period of oscillation, t = 0.94 s

It is assumed to find the moment of inertia of the wrench about an axis through the pivot. the time period of the oscillation is given by :

So, the moment of inertia of the wrench about an axis through the pivot is . Hence, this is the required solution.                                                                              

+15-35=-20

going in opposite directions

the components of a vector are the parts of the vectors that are to each other.

b perpendicular