Ashot-putter puts a shot (weight=71.1n) that leaves his hand at adistance of 1.52m above the ground. (a) find the work done by thegravitational force when the shot has risen to a height of 2.13mabove the ground. (b) determine the change(δpe=pefinal-peinitial) in the gravitationalpotential energy of the shot.

need with b

Explanation:

It is given that,

weight of the shot- putter, W = 71.1 kg

Initial position,

Final position,

To find,

Work done and the change in potential energy.

Solution,

(a) Let W is the work done by the gravitational force when the shot has risen to a height of 2.13 m above the ground. It is given by :

(b) We know that the potential energy is equal to the work done by an object such that,