Asimple, harmonic oscillator at the point x=0 generates a wave on a rope. the oscillator operates at a frequency of 40 hz and with an amplitude of 3.00 cm. the rope has a linear mass density of 50.0 g/m and is stretched with a tension of 5.00 n.

Answer

given,

Frequency of oscillator = 40 Hz

Amplitude = 3 cm

linear mass density of rope = 50 x 10⁻³ kg/m

tension = T = 5 N

calculating the speed of wave

μ is linear mas density of rope

        v = 10 m/s

now, calculating the wavelength of the

    λ = 0.25 m

now calculating transverse acceleration

 a = A ω²

 ω = 2 π f

 ω = 2 π x 40 = 251.32 /m

 a = 0.03 x 251.32²

a = 1894.96 m/s²

explanation:

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