You push down on the car to provide more friction for the tires allowing the cars tires to propel it forward 5 meters. how much work do you do?

The work done by you, W = 9800 J

Explanation:

Given data,

The displacement of the car, S = 5 m

Let the mass of the car be, m = 2000 kg

Let the coefficient of static friction be 0

Hence, no frictional force is acting on the tire and ground.

Let, you push down the car to provide more friction, μₓ = 0.1 (you can change the value)

In order to provide the static friction, you push down the car is equal to the static friction force,

                                      Fₓ =  μₓ · η

Where,

                                 η - normal force acting on the car (mg)

Substituting the values,

                                   Fₓ = 0.1 x 2000 x 9.8

                                       = 1960 N  

Therefore work done,

                                   W = Fₓ x S

                                        = 1960 N x 5 m

                                        = 9800 J

Hence, the work done by you, W = 9800 J

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.