Aquantity of an ideal gas is kept in a rigid container of constant volume. if the gas is originally at a temperature of 28 °c, at what temperature (in °c) will the pressure of the gas triple from its base value?

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Explanation:

Original temperature of the gas,

From the ideal gas equation,

Since,

or

So, the new temperature of the gas is 630 degree Celsius. Hence, this is the required solution.

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases . this process does not change the mass number.

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as -decay. in this the mass number remains same.

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

heat the gas and measure the pressure